One angle of an isosceles triangle is `120^0` and the radius of its incircle is `sqrt(3)dot` Then the area of the triangle in sq. units is
(a) `7+12sqrt(3)` (b) `12-7sqrt(3)` (c) `12+7sqrt(3)` (d) `4pi`

Explanation

To solve the problem, we need to find the area of an isosceles triangle given that one angle is \(120^\circ\) and the radius of its incircle is \(\sqrt{3}\).

### Step-by-Step Solution:

1. **Identify the Triangle Properties**:
- Let the two equal sides of the isosceles triangle be \(x\).
- The base (the third side) will be denoted as \(a\).
- The angles of the triangle are \(120^\circ\) (given) and the other two angles will be \(30^\circ\) each (since the sum of angles in a triangle is \(180^\circ\)).
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