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If cos28^0+sin28^0=k^3, t h e ncos17^0 ...

If `cos28^0+sin28^0=k^3, t h e ncos17^0` is equal to (a)`(k^3)/(sqrt(2))` (b) `-(k^3)/(sqrt(2))` (c) `+-(k^3)/(sqrt(2))` (d) none of these

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