`(sin^2A-sin^2B)/(sinAcosA-sinBcosB)`is equal to (a)`"tan"(A-B)` (b) `"tan"(A+B)` `cot(A-B)` (d) `cot(A+B)`

Explanation

To solve the expression \((\sin^2 A - \sin^2 B) / (\sin A \cos A - \sin B \cos B)\), we can follow these steps:

### Step 1: Use the difference of squares in the numerator
The numerator \(\sin^2 A - \sin^2 B\) can be factored using the identity for the difference of squares:
\[ \sin^2 A - \sin^2 B = (\sin A + \sin B)(\sin A - \sin B) \]

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