If cos25^0+sin25^0=p , then cos50^0 is...

If `cos25^0+sin25^0=p ,` then `cos50^0` is (a)`sqrt(2-p^2)` (b) `-sqrt(2-p^2)` (c)`psqrt(2-p^2)` (d) `-psqrt(2-p^2)`

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To solve the problem, we start with the given equation: 1. **Given**: \[ \cos 25^\circ + \sin 25^\circ = p \] 2. **Square both sides**: ...

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