If `tan(alpha-beta)=(sin2beta,)/(3-cos2beta)` then (a)`tanalpha=2tanbeta` (b) `tanbeta=2tanalpha` (c)`2tanalpha=3tanbeta` (d) `3tanalpha=2tanbeta`

If tan (alpha-beta)=(sin 2beta)/(3-cos 2beta) , then

(1+tanalphatanbeta)^2+(tanalpha-tanbeta)^2=

(1+tanalphatanbeta)^2+(tanalpha-tanbeta)^2=

If tanalpha=(1-cosbeta)/(sinbeta),t h e n (a) tan3alpha=tan2beta (b) tan2alpha=tanbeta (c) tan2beta=tanalpha (d) none of these

cos 2 alpha =(3 cos 2 beta -1)/( 3-cos 2 beta), then tan alpha=

If alphaa n dbeta are acute angles satisfying cos2alpha=(3cos2beta-1)/(3-cos2beta),t h e ntanalpha= sqrt(2)tanbeta (b) 1/(sqrt(2))t a nbeta (c) sqrt(2)cotbeta (d) 1/(sqrt(2))cotbeta

tanalpha.tan(60^@-alpha).tan(60^@+alpha)=tan3alpha

Let alpha,betaa n dgamma be some angles in the first quadrant satisfying tan(alpha+beta)=(15)/8a n dcos e cgamma=(17)/8, then which of the following hold(s) good? (a) alpha+beta+gamma=pi (b) cotalpha+cotbeta+cotgamma=cotalphacotbetacotgamma (c) tanalpha+tanbeta+tangamma=tanalphatanbetatangamma (d) tanalphatanbeta+tanbetatangamma+tangammatanalpha=1

if tan alpha = 2tanbeta show that (sin(alpha+beta))/(sin(alpha-beta)) = 3

If tanalpha+cotalpha=2 , then