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If cos^(-1)x+cos^(-1)y+cos^(-1)z=pi,t h ...

If `cos^(-1)x+cos^(-1)y+cos^(-1)z=pi,t h e n` `x^2+y^2+z^2+2x y z=1` `2(sin^(-1)x+sin^(-1)y+sin^(-1)z)=cos^(-1)x+cos^(-1)y+cos^(-1)z` `x y+y z+z x=x+y+z-1` `(x+1/x)+(y+1/y)+(z+1/z)geq6`

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To solve the problem step by step, we start with the given equation: 1. **Given Equation**: \[ \cos^{-1} x + \cos^{-1} y + \cos^{-1} z = \pi \] 2. **Using the Identity**: ...
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