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If sin^(-1)(x^2-4x+5)+cos^(-1)(y^2-2y+2)...

If `sin^(-1)(x^2-4x+5)+cos^(-1)(y^2-2y+2)=pi/2` then find the value of `xa n dydot`

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To solve the equation \( \sin^{-1}(x^2 - 4x + 5) + \cos^{-1}(y^2 - 2y + 2) = \frac{\pi}{2} \), we can follow these steps: ### Step 1: Use the Identity We know that: \[ \sin^{-1}(a) + \cos^{-1}(a) = \frac{\pi}{2} \] for any \( a \) in the domain of the inverse trigonometric functions. This means: ...
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