Find the domain for `f(x)=sin^(-1)((1+x^2)/(2x))`

Explanation

To find the domain of the function \( f(x) = \sin^{-1}\left(\frac{1+x^2}{2x}\right) \), we need to ensure that the expression inside the inverse sine function lies within the range of \([-1, 1]\).

### Step-by-Step Solution:

1. **Set Up the Inequality**:
We need to solve the inequalities:
\[
-1 \leq \frac{1+x^2}{2x} \leq 1
...