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If cos^(-1)((6x)/(1+9x^2))=-pi/2+2tan^(-...

If `cos^(-1)((6x)/(1+9x^2))=-pi/2+2tan^(-1)3x ,` then find the value of`xdot`

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To solve the equation \( \cos^{-1}\left(\frac{6x}{1+9x^2}\right) = -\frac{\pi}{2} + 2\tan^{-1}(3x) \), we will follow these steps: ### Step 1: Rewrite the Equation We start with the given equation: \[ \cos^{-1}\left(\frac{6x}{1+9x^2}\right) = -\frac{\pi}{2} + 2\tan^{-1}(3x) \] ...
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