If the period of `(cos(sin(n x)))/(tan(x/n)),n in N ,i s6pi` , then `n=` (a)3 (b) 2 (c) 6 (d) 1

period the function f(x)=(sin{sin(n x)})/(tan (x/n)) , n in N, is 6pi then n= --------

The period of f(x)=sin((pix)/(n-1))+ cos ((pix)/(n)), n in Z, n gt 2 , is

The value of int_0^pi (sin(n+1/2)x)/(sin (x/2)) dx is, (a) n in I, n >= 0 pi/2 (b) 0 (c) pi (d) 2pi

Which of the following is not the general solution of 2^(cos2x)+1=3. 2^(-sin^2 x)? (a) npi,n in Z (b) (n+1/2)pi,n in Z (c) (n-1/2)pi,n in Z (d) none of these

tan^(-1)n ,tan^(-1)(n+1) and tan^(-1)(n+2),n in N , are the angles of a triangle if n= 1 (b) 2 (c) 3 (d) None of these

The general solution of cosxcos6x=-1 is (a) x=(2n+1)pi,n in Z (b) x=2npi,n in Z (c) x=npi,n in Z (d) none of these

IfA_n=int_0^(pi/2)(sin(2n-1)x)/(sinx)dx ,b_n=int_0^(pi/2)((sinn x)/(sinx))^2dxforn in N , Then (a) A_(n+1)=A_n (b) B_(n+1)=B_n (c) A_(n+1)-A_n=B_(n+1) (d) B_(n+1)-B_n=A_(n+1)

If the value of "^(n)C_(0)+2*^(n)C_(1)+3*^(n)C_(2)+...+(n+1)*^(n)C_(n)=576 , then n is (a) 7 (b) 5 (c) 6 (d) 9

If A_n=int_0^(pi/2)(sin(2n-1)x)/(sinx)dx ,B_n=int_0^(pi/2)((sinn x)/(sinx))^2 dx for n inN , Then (A) A_(n+1)=A_n (B) B_(n+1)=B_n (C) A_(n+1)-A_n=B_(n+1) (D) B_(n+1)-B_n=A_(n+1)

Find the point of inflection of the function: f(x)=sin x (a) 0 (b) n pi,n in Z (c) (2n+1)(pi)/(2),n in Z (d) None of these