Consider the function `f(x)={2x+3,xlt=1-x^2+6,x >1`

Consider the function f(x)={2x+3, x le 1 and -x^2+6, x > 1} Then draw the graph of the function y=f(x), y=f(|x|) and y=|f(x)|.

Consider the functions f(x)={(x+1",",x le 1),(2x+1",",1lt x le 2):} and g(x)={(x^(2)",", -1 le x lt2),(x+2",",2le x le 3):} The range of the function f(g(x)) is

Consider the function f(x)=(x^(3)-x)|x^(2)-6x+5|, AA x in R , then f(x) is

Consider the function f(x)=max. [(x^(2) , (1-x)^(2) , 2x(1-x))] , x in [0,1] The interval in which f(x) is increasing, is

The value of b for which the function f(x)={5x-4,0xlt=1 , 4x^2+3b x ,1< x <2 and continuous at x=1

Consider the function f(x) = 2x + 3 and we want to find the limit of this function at x = 1.

Consider the function f(x) = |x^(3) + 1| . Then,

Consider the function f(x)=((ax+1)/(bx+2))^(x) , where a,bgt0 , the lim_(xtooo)f(x) is

If the function f(x)={A x-B ,xlt=1 3x ,1

Consider the function f(x)=(.^(x+1)C_(2x-8))(.^(2x-8)C_(x+1)) Statement-1: Domain of f(x) is singleton. Statement 2: Range of f(x) is singleton.