If `f` is periodic, `g` is polynomial function and `f(g(x))` is periodic and `g(2)=3,g(4)= 7` then `g(6)` is

If f is a periodic function and g is a non-periodic function , then

If f(x) and g(x) are non-periodic functions, then h(x)=f(g(x)) is

Statement-1 : f(x) = [{x}] is a periodic function with no fundamental period. and Statement-2 : f(g(x)) is periodic if g(x) is periodic.

If f(x) and g(x) are polynomial functions of x, then domain of (f(x))/(g(x)) is

f:R to R is a function defined by f(x)= 10x -7, if g=f^(-1) then g(x)=

if f(x) and g(x) are continuous functions, fog is identity function, g'(b) = 5 and g(b) = a then f'(a) is

If f(x), g(x) be twice differentiable function on [0,2] satisfying f''(x)=g''(x) , f'(1)=4 and g'(1)=6, f(2)=3, g(2)=9, then f(x)-g(x) at x=4 equals to:- (a) -16 (b) -10 (c) -8

Statement-1: Function f(x)=sin(x+3 sin x) is periodic . Statement-2: If g(x) is periodic then f(g(x)) periodic

Let f(x)=sinx ,g(x)=cosx , then which of the following statement is false period of f(g(x)) is 2pi period of f(g(x)) is pi f(g(x)) is an odd function f(g(x)) is an even function

Let f(x) be a periodic function with period int_0^x f(t+n) dt 3 and f(-2/3)=7 and g(x) = .where n=3k, k in N . Then g'(7/3) =