If `f(x)=max{x^3, x^2,1/(64)}AAx in [0,oo),t h e n` `f(x)={x^2,0lt=xlt=1x^3,x > 0` `f(x) = { 1/(64), 0 lt= x lt = 1/4 x^2, 1/4 < xlt= 1x^3, x > 1` `f(x)={1/(64),0lt=xlt=1/8x^2,1/8 < xlt=1x^3,x >1` `f(x)={1/(64),0lt=xlt=1/8x^3,x >1/8`

Find f(x) when it is given by f(x)=max{x^(3),x^(2),(1)/(64)},AA x in [0, oo).

Show that f(x)={1+x^2,if0lt=xlt=1 and 2-x if x >1 is discontinuous at x=1

f(x)={(4, xlt-1) ,(-4x,-1lt=xlt=0):} If f(x) is an even function in R then the definition of f(x) in (0,oo) is: (A) f(x)={(4x, 0ltxle1),(4, xgt1):} (B) f(x)={(4x, 0ltxle1),(-4, xgt1):} (C) f(x)={(4, 0ltxle1),(4x, xgt1):} (D) f(x)={(4, xlt-1),(-4x, -1lexle0):}

Let f(x)=x^3-3x^2+6AAx in \mathbb{R} and g(x)={m a x :f(t ; x+1lt=tlt=x+2,-3lt=xlt=0 1-x ,xgeq

Let f(x)= {{:(1+ sin x, x lt 0 ),(x^2-x+1, x ge 0 ):}

The function f(x)= {(5x-4 ", " 0 lt x le 1 ),( 4x^3-3x", " 1 lt x lt 2):}

Find the equivalent definition of f(x)=max{x^2,(1-x)^2,2x(1-x)} where 0lt=xlt=1

Let f(x)={x+1,x >0, 2-x ,xlt=0 and g(x)={x+3,x 0)g(f(x)).

If (f(x))^(2)xxf((1-x)/(1+x))=64x AAx in D_(f), then The domain of f(x) is

Evaluate the following integral: int_0^9f(x)dx ,\ w h e r e\ f(x)=sinx,\ 0lt=xlt=pi//2 w h e r e\ f(x)= 1 ,pi/2lt=xlt=3 w h e r e\ f(x)=e^(x-3),\ 3lt=xlt=9