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Let g(x)=1+x-[x] and f(x)={-1,x < 0, 0...

Let `g(x)=1+x-[x] and f(x)={`-1,x < 0`, `0, x=0` , `1, x > 0.` Then for all x, `f(g(x))` is equal to `(where [.] represents the greatest integer function).` (a) `x` (b) `1` (c) `f(x)` (d) `g(x)`

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