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Determine the number of terms in a G.P., if `a_1=3,a_n=96 ,a n dS_n=189.`

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Determine the number of terms in G.P. >,ifa_1=3,a_n=96a n dS_n=189.

Determine the number of terms in G.P. if a_1=3,a_n=96 and S_n=189 .

The sum of terms of a G.P if a_(1)=3,a_(n)=96 and S_(n)=189 is

The first and last term of a geometrical Pregression (G.P.) are 3 and 96 respectively. If the common ratio is 2, find : (i) 'n' the number of terms of the G.P. (ii) Sum of the n terms.

Find the first four terms of the sequence defined by a_1=3\ a n d\ a_n=3a_(n-1)+2 , for all n >1.

Find the first four terms of the sequence defined by a_1=3\ a n d\ a_n=3a_(n-1)+2 , for all n .1.

Write the first five terms in each of the following sequence: a_1=1,\ a_n=a_(n-1)+2,\ n >1

Write the first three terms of the sequence defined by a_1= 2,a_(n+1)=(2a_n+3)/(a_n+2) .

Write the first five terms in each of the following sequence: a_1=a_2=2,\ a_n=a_(n-1)-1,\ n >1 .

Write the first five terms of the sequence and obtain the corresponding series : a_1=3,a_n=3a_(n-1)+2 for all n > 1

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  3. Determine the number of terms in a G.P., if a1=3,an=96 ,a n dSn=189.

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