If `x ,y in R a n d2x^2+6x y+5y^2=1,t h e n` a. `|x|lt=sqrt(5)` b. `|x|geqsqrt(5)` c. `y^2lt=2` d. `y^2lt=4`

{x:x=2y +5, y in N " and " 2 le y lt 6}

If 9x^2+25 y^2=181\ \ a n d\ x y\ =\ -6, find the value of 3x+5y

x + y ge 4, 2x - y lt 0

If 3x+5y=11\ a n d\ x y=2, find the value of 9x^2+25 y^2

x y=(x+y)6na n d(dy)/(dx)=y/x t h e nn= 1 b. 2 c. 3 d. 4

The centers of a set of circles, each of radius 3, lie on the circle x^2+y^2=25 . The locus of any point in the set is 4lt=x^2+y^2lt=64 x^2+y^2lt=25 x^2+y^2geq25 (d) 3lt=x^2+y^2lt=9

If P=7x^2+5x y-9y^2,\ Q=4y^2-3x^2-6x y and R=-4x^2+x y+5y^2, show that P+Q+R=0.

If 2x^2y\ a n d\ 3x y^2 denote the length and breadth of a rectangle, then its area is (a) 6x y (b) 6x^2y^2 (c) 6x^3y^3 (d) x^3y^3

The ellipse 4x^2+9y^2=36 and the hyperbola a^2x^2-y^2=4 intersect at right angles. Then the equation of the circle through the points of intersection of two conics is (a) x^2+y^2=5 (b) sqrt(5)(x^2+y^2)-3x-4y=0 (c) sqrt(5)(x^2+y^2)+3x+4y=0 (d) x^2+y^2=25

Find the area of the region {(x , y): x^2+y^2lt=1lt=x+y}dot