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If p=a+bomega+comega^2, q=b+comega+aomeg...

If `p=a+bomega+comega^2`, `q=b+comega+aomega^2`, and `r=c+aomega+bomega^2`, where `a ,b ,c!=0` and `omega` is the complex cube root of unity, then (a) `p+q+r=a+b+c` (b) `p^2+z^2+r^2=a^2+b^2+c^2` (c) `p^2+z^2+r^2=-2(p q+q r+r p)` (d) none of these

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