If `a^2+b^2=1` t h e n ` (1+b+i a)/(1+b-i a)=` `1` b. `2` c. `b+i a` d. `a+i b`

If z(1+a)=b+i ca n da^2+b^2+c^2=1, then [(1+i z)//(1-i z)= A. (a+i b)/(1+c) B. (b-i c)/(1+a) C. (a+i c)/(1+b) D. none of these

If A=[[a+i b, c+i d],[-c+i d, a-i b]] and a^2+b^2+c^2+d^2=1,t h e n ,A^(-1) is equal to a. [[a+i b,-c+i d],[c+i d, a-i b]] b. [[a-i b,-c-i d],[-c-i d, a+i b]] c. [[a+i b,-c-i d],[-c+i d, a-i b]] d. none of these

Let x_1, x_2, ,x_n be x_n observations. Let y_i=a x_i+b for i=1,2,...,n where a and b are constants. If the mean of x_i's is 48 and their standard deviation is 12, the mean of y_i 's is 55 and standard deviation of y_i's is 15, the values of a and b are (a) a=1. 25 ,b=-5 (b) a=-1. 25 ,b=5 (c) a=2. 5 ,b=-5 (d) a=2. 5 ,b=5

Let x_1, x_2, ,x_n be x_n observations. Let y_i=a x_i+b for i=1,2,...,n where a and b are constants. If the mean of x_i's is 48 and their standard deviation is 12, the mean of y_i 's is 55 and standard deviation of y_i's is 15, the values of a and b are (a) a=1. 25 ,b=-5 (b) a=-1. 25 ,b=5 (c) a=2. 5 ,b=-5 (d) a=2. 5 ,b=5

If a=1+i , then a^2 equals A. 1-i B. 2i C. (1+i)(1-i) D. (i-1)

If i^2=-1, then the sum i+i^2+i^3+... upto 1000 terms is equal to a. 1 b. -1 c. i d. 0

If A=[[1,-1],[ 2, 1]],B=[[a,1],[b,-1]]a n d(A+B)^2=A^2+B^2+2A B ,t h e n a. a=-1 b. a=1 c. b=2 d. b=-2

If x(t) is a solution of ((1+t)dy)/(dx)-t y=1 and y(0)=-1 then y(1) is (a) ( b ) (c)-( d )1/( e )2( f ) (g) (h) (i) (b) ( j ) (k) e+( l )1/( m )2( n ) (o) (p) (q) (c) ( d ) (e) e-( f )1/( g )2( h ) (i) (j) (k) (d) ( l ) (m) (n)1/( o )2( p ) (q) (r) (s)

The value of (1+i)(1+i^2)(1+i^3)(1+i^4) is a. 2 b. 0 c. 1 d. i

If b_i=1-a_i ,n a=sum_(i=1)^n a_i ,n b=sum_(i=1)^n b_i ,t h e nsum_(i=1)^n a_i ,b_i+sum_(i=1)^n(a_i-a)^2= a b b. n a b c. (n+1)a b d. n a b