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Let Zp=rp(costhetap+isinthetap),p=1,2,3a...

Let `Z_p=r_p(costheta_p+isintheta_p),p=1,2,3a n d1/(Z_1)+1/(Z_2)+1/(Z_3)=0.` Consider the ` A B C` formed formed by `(cos2theta_1+isin2theta_1)/(Z_1),(cos2theta_2+isin2theta_2)/(Z_2),(cos2theta_3+isin2theta_3)/(Z_3)` Prove that origin lies inside triangle `A B Cdot`

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