Find the point of intersection of the curves `a r g(z-3i)=(3pi)/4a n d arg(2z+1-2i)=pi//4.`

Explanation

To find the point of intersection of the curves given by the equations \( \arg(z - 3i) = \frac{3\pi}{4} \) and \( \arg(2z + 1 - 2i) = \frac{\pi}{4} \), we will analyze each equation step by step.

### Step 1: Analyze the first curve
The first curve is given by the equation:
\[ \arg(z - 3i) = \frac{3\pi}{4} \]
This means that the point \( z \) lies on a line that originates from the point \( 0 + 3i \) (which is the point \( (0, 3) \) in the complex plane) and makes an angle of \( \frac{3\pi}{4} \) with the positive real axis.
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