If `|z_1-z_0|=|z_2-z_0|=a` and `amp((z_2-z_0)/(z_0-z_1))=pi/2` , then find `z_0`

If |z_1-z_0|=z_2-z_1=pi/2 , then find z_0 .

If |z_(1)|=|z_(2)| and arg (z_(1)//z_(2))=pi, then find the of z_(1)z_(2).

If |z_(1)|=|z_(2)|andamp(z_(1))+amp(z_(2))=0, then

If |z_1|=|z_2| and arg((z_1)/(z_2))=pi , then z_1+z_2 is equal to (a) 0 (b) purely imaginary (c) purely real (d) none of these

If z_1=2-i ,z_2=1+i , find |(z_1+z_2+1)/(z_1-z_2+i)|

If z_1,z_2,z_3,z_4 be the vertices of a parallelogram taken in anticlockwise direction and |z_1-z_2|=|z_1-z_4|, then sum_(r=1)^4(-1)^r z_r=0 (b) z_1+z_2-z_3-z_4=0 a r g(z_4-z_2)/(z_3-z_1)=pi/2 (d) None of these

If |z_(1)|=|z_(2)| and arg (z_(1))+"arg"(z_(2))=0 , then

If z_1a n dz_2 both satisfy z+ z =2|z-1| and a r g(z_1-z_2)=pi/4 , then find I m(z_1+z_2) .

Let z_1, z_2, z_3 be the three nonzero complex numbers such that z_2!=1,a=|z_1|,b=|z_2|a n d c=|z_3|dot Let |a b c b c a c a b|=0 a r g(z_3)/(z_2)=a r g((z_3-z_1)/(z_2-z_1))^2 orthocentre of triangle formed by z_1, z_2, z_3, i sz_1+z_2+z_3 if triangle formed by z_1, z_2, z_3 is equilateral, then its area is (3sqrt(3))/2|z_1|^2 if triangle formed by z_1, z_2, z_3 is equilateral, then z_1+z_2+z_3=0

If |z_1|=|z_2|=|z_3|=1 and z_1+z_2+z_3=0 then the area of the triangle whose vertices are z_1, z_2, z_3 is 3sqrt(3)//4 b. sqrt(3)//4 c. 1 d. 2