If `((1+i)/(1-i))^m=1,` then find the least positive integral value of `mdot`

Explanation

To solve the equation \(\left(\frac{1+i}{1-i}\right)^m = 1\), we need to find the least positive integral value of \(m\).

### Step-by-Step Solution:

1. **Simplify the expression**:
We start with the expression \(\frac{1+i}{1-i}\). To simplify this, we multiply the numerator and denominator by the conjugate of the denominator, which is \(1+i\):
\[
\frac{1+i}{1-i} \cdot \frac{1+i}{1+i} = \frac{(1+i)(1+i)}{(1-i)(1+i)}
...