The number of integral value of `x` satistying `sqrt( x^2+10 x-16)ltx-2` is

Explanation

To solve the inequality \( \sqrt{x^2 + 10x - 16} < x - 2 \) and find the number of integral values of \( x \) that satisfy it, we can follow these steps:

### Step 1: Determine the domain of the square root
The expression inside the square root must be non-negative:
\[ x^2 + 10x - 16 \geq 0 \]
To find the roots, we can use the quadratic formula:
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