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If the roots of the equation x^2-ax+b=0y...

If the roots of the equation `x^2-ax+b=0`y are real and differ b a quantity which is less than `c(c >0),` then show that `b` lies between `(a^2-c^2)/4` and `a^2/4.`

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CENGAGE ENGLISH-COMPLEX NUMBERS AND QUADRATIC EQUATIONS-All Questions
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