If the 3rd, 4th , 5th and 6th term in the expansion of `(x+alpha)^n` be, respectively, `a ,b ,ca n dd ,` prove that `(b^2-a c)/(c^2-b d)=(5a)/(3c)dot`

Explanation

To solve the problem, we need to find the values of the 3rd, 4th, 5th, and 6th terms in the expansion of \((x + \alpha)^n\) and then prove the given expression. Let's go through the solution step by step.

### Step 1: Identify the terms in the binomial expansion
The general term \(T_r\) in the binomial expansion of \((x + \alpha)^n\) is given by:
\[ T_r = \binom{n}{r-1} x^{n-(r-1)} \alpha^{r-1} \]
where \(r\) is the term number.
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