In `( 2^(1/3)+1/3^(1/ 3))^n` if the ratio of 7th term from the beginning to the 7th term from the end is 1/6, then find the value of `ndot`

Options

A. `6`
B. `9`
C. `12`
D. `15`

Explanation

To solve the problem, we need to find the value of \( n \) in the expression \( (2^{1/3} + \frac{1}{3^{1/3}})^n \) given that the ratio of the 7th term from the beginning to the 7th term from the end is \( \frac{1}{6} \).

### Step-by-Step Solution:

1. **Identify the General Term**:
The general term \( T_r \) in the expansion of \( (a + b)^n \) is given by:
\[
T_r = \binom{n}{r-1} a^{n-(r-1)} b^{r-1}
...