`(d^2x)/(dy^2)` equals: (1) `((d^2y)/(dx^2))^-1` (2) `-((d^2y)/(dx^2))^-1 ((dy)/(dx))^-3` (3) `-((d^2y)/(dx^2))^-1 ((dy)/(dx))^-2` (4) `-((d^2y)/(dx^2))^-1 ((dy)/(dx))^3`

(d^2x)/(dy^2) equals: (1.) ((d^2y)/(dx^2))^-1 (2) -((d^2y)/(dx^2)) ((dy)/(dx))^-3 (3) -((d^2y)/(dx^2))^-1 ((dy)/(dx))^-2 (4) -((d^2y)/(dx^2))^-1 ((dy)/(dx))^3

Solve (d^2y)/(dx^2)=((dy)/(dx))^2

Solve (d^2y)/(dx^2)=((dy)/(dx))^2

If x=logp and y=1/p ,then (a) (d^2y)/(dx^2)-2p=0 (b) (d^2y)/(dx^2)+y=0 (c) (d^2y)/(dx^2)+(dy)/(dx)=0 (d) (d^2y)/(dx^2)-(dy)/(dx)=0

If y=xlog(x/(a+b x)),t h e nx^3(d^2y)/(dx^2)= (a) x(dy)/(dx)-y (b) (x(dy)/(dx)-y)^2 y(dy)/(dx)-x (d) (y(dy)/(dx)-x)^2

If e^y(x+1)=1 , show that (d^2y)/(dx^2)=((dy)/(dx))^2 .

If e^y(x+1)=1 , show that (d^2y)/(dx^2)=((dy)/(dx))^2 .

If R=([1+((dy)/(dx))^2]^(3//2))/((d^2y)/(dx2)) , then R^(2//3) can be put in the form of a. 1/(((d^2y)/(dx^2))^(2//3))+1/(((d^2x)/(dy^2))^(2//3)) b. 1/(((d^2y)/(dx^2))^(2//3))-1/(((d^2x)/(dy^2))^(2//3)) c. 2/(((d^2y)/(dx^2))^(2//3))+2/(((d^2x)/(dy^2))^(2//3)) d. 1/(((d^2y)/(dx^2))^(2//3))1/(((d^2x)/(dy^2))^(2//3))

If R=([1+((dy)/(dx))^2]^(-3//2))/((d^2y)/(dx2)) , then R^(2//3) can be put in the form of 1/(((d^2y)/(dx^2))^(2//3))+1/(((d^2x)/(dy^2))^(2//3)) b. 1/(((d^2y)/(dx^2))^(2//3))-1/(((d^2x)/(dy^2))^(2//3)) c. 2/(((d^2y)/(dx^2))^(2//3))+2/(((d^2x)/(dy^2))^(2//3)) d. 1/(((d^2y)/(dx^2))^(2//3))dot1/(((d^2x)/(dy^2))^(2//3))

If e^(y) (x+1) =1 show that (d^(2) y)/( dx^(2)) = ((dy)/(dx))^(2)