A seven-digit number without repetition and divisible by 9 is to be formed by using seven digits out of `1, 2, 3, 4, 5, 6, 7, 8, 9.` The number of ways in which this can be done is (a) `9!` (b) `2(7!)` (c) `4(7!)` (d) non of these

An eight digit number divisible by 9 is to be formed using digits from 0 to 9 without repeating the digits. The number of ways in which this can be done is

A five-digit number divisible by 3 is to be formed using the digits 0, 1, 2, 3, 4, and 5, without repetition. The total number of ways this can done is

A five digit number divisible by 3 is to be formed using the digits 0,1,3,5,7,9 without repetitions. The total number of ways this can be done is

A five digit number divisible by 3 is to be formed using the numerals 0, 1, 2, 3, 4 and 5, without repetition. The total number of ways this can be done, is

The number of five-digit numbers which are divisible by 3 that can be formed by using the digits 1,2,3,4,5,6,7,8 and 9 , when repetition of digits is allowed, is

How many four-digit numbers can be formed by using the digits 1, 2, 3, 4, 5, 6, 7 if at least one digit is repeated.

How many four-digit numbers can be formed by using the digits 1, 2, 3, 4, 5, 6, 7 if at least one digit is repeated.

A three-digit number is to be formed using the digits 0, 1, 2, 3, 4, and 5, without repetition.

The number of distinct natural numbers up to a maximum of four digits and divisible by 5, which can be formed with the digits 0, 1 , 2, 3, 4, 5, 6, 7, 8, 9 each digit not occurring more than once in each number, is a. 1246 b. 952 c. 1106 d. none of these

How many even numbers of 5 digits without repetition can be formed with the digits 1,2,3,4 and 5.