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Prove that [(a^2+b^2)/(a+b)]^(a+b)> a^a ...

Prove that `[(a^2+b^2)/(a+b)]^(a+b)> a^a b^b >{(a+b)/2}^(a+b)dot`

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  3. Prove that [(a^2+b^2)/(a+b)]^(a+b)> a^a b^b >{(a+b)/2}^(a+b)dot

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