A student is allowed to select at most n books from a collection of (2n+1) books. If the total number of ways in which a student selects at least one book is 63. then n equals to -

A student is allowed to select atmost n books from a collection of (2n+1) books. If the total number of ways in which a student selects atleast one book is 63, then n equals to what?

Statement-1: A student is allowed to select at most n books from a collection of (2n+1) books. If the total number of ways in which he can select at least one book is 255, then n=3. Statement-2 sum_(r=1)^(n)""^(2n+1)C_(r)=2^(2n)

A student is allowed to select at most n books from a collection of (2n+1) books .If the total number of ways in which he can select books is 63 find the value of n.

A person is permitted to selected at least one and at most n coins from a collection of (2n+1) distinct coins. If the total number o ways in which he can select coins is 255, find the value of ndot

There are p copies each of n different books. Find the number of ways in which a nonempty selection can be made from them.

There are p copies each of n different books. Find the number of ways in which a nonempty selection can be made from them.

A team of four students is to be selected from a total of 12 students. The total number of ways in which the team can be selected such that two particular students refuse to be together and other two particular students wish to be together only is equal to a. 220 b. 182 c. 226 d. none of these

A shopkeeper has 11 copies each of nine different books, then the number of ways in which atleast one book can be selected is

A library has a copies of one book, b copies each of two books, c copies each of three books, a single copy of d books. The total number of ways in which these books can be arranged in a shelf is equal to a. ((a+2b+3c+d)!)/(a !(b !)^2(c !)^3) b. ((a+2b+3c+d)!)/(a !(2b !)^(c !)^3) c. ((a+b+3c+d)!)/((c !)^3) d. ((a+2b+3c+d)!)/(a !(2b !)^(c !)^)

A library has a copies of one book, b copies each of two books, c copies each of three books, a single copy of d books. The total number of ways in which these books can be arranged in a shelf is equal to a. ((a+2b+3c+d)!)/(a !(b !)^2(c !)^3) b. ((a+2b+3c+d)!)/(a !(2b !)^(c !)^3) c. ((a+b+3c+d)!)/((c !)^3) d. ((a+2b+3c+d)!)/(a !(2b !)^(c !)^)