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Find the number of ways of dividing 52 cards among four players equally.

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The number of ways of dividing equally a pack of 52 playing cards among 4 players is (A) 52!/13! (B) 52!/((13!)^2) (C) 52!/((13!)^2) (D) 52!/((13!))^4

Find the numbers of ways of arranging 6 players to throw the cricket ball so that the oldest players may not throw first.

What is the number of ways of choosing 4 cards from a pack of 52 playing cards? In how many of these Four cards are of the same suit? For cards are face cards? Cards are of the same colour? Four cards belong to four different suits? Two aqre red cards and two are black cards?

What is the number of ways of choosing 4 cards from a pack of 52 playing cards? In how many of these(i) four cards are of the same suit,(ii) four cards belong to four different suits,(iii) are face cards,(iv) two are red cards and two are black cards,(v) cards are of the same colour?

There are seven even greeting cards each of a different colour and seven envelopes of the same seven colours. Find the number of ways in which the cards can be put in the envelopes so that exactly four of the cards go into the envelopes of the right colour.

Find the number of ways in which 4 cards can be selected from a pack of 52 cards. In how many ways (i) all 4 cards are from one suit? (ii) all 4 cards are from different suits? (iii) all 4 cards are face cards? (iv) two cards are red and 2 cards are black? (v) all 4 cards are of same colour?

In how many ways can 52 cards be divided among 4 players equally, when (i) each gets equal number of cards? (ii) cards are divided into 4 groups of 14 cards each?

The number of ways to distribute m xx n different thing among n persons equally = ((mn)!)/((m!)^(n)) The numbers of ways in which a particular player holds all the aces and all of them equal number is

Find the numbers of ways in which 12 apples may be eqully divided among 3 childrens.

The number of ways to distribute m xx n different thing among n persons equally = ((mn)!)/((m!)^(n)) The number of ways in which 12 different books can be divided equally in 3 heaps of book is

CENGAGE ENGLISH-PERMUTATIONS AND COMBINATIONS-All Questions
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  2. Statement 1: Total number of five-digit numbers having all differen...

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