The next term of the G.P. `x ,x^2+2,a n dx^3+10` is `(729)/(16)` b. `6` c. `0` d. `54`

Write the next four terms of the A.P. 2,-2,-6,-10,..........

The 4th and 7th terms of a G.P. are 1/(27)a n d1/(729) respectively. Find the sum of n terms of the G.P.

The first and second terms of a G.P. are x^4a n dx^n , respectively. If x^(52) is the 8th term, then find the value of ndot

Find the next two terms of the series : 2-6+18-54 . . . . . . . . . . . . .

Consider a G.P. with first term (1+x)^(n) , |x| lt 1 , common ratio (1+x)/(2) and number of terms (n+1) . Let S be sum of all the terms of the G.P. , then sum_(r=0)^(n)"^(n+r)C_(r )((1)/(2))^(r ) equals (a) 3/4 (b) 1 (c) 2^n (d) 3^n

If x ,2x+2 and 3x+3 are the first three terms of a G.P., then the fourth term is a. 27 b. -27 c. 13.5 d. -13.5

If x ,2y ,3z are in A.P., where the distinct numbers x ,y ,z are in G.P, then the common ratio of the G.P. is a. 3 b. 1/3 c. 2 d. 1/2

In a sequence of (4n+1) terms, the first (2n+1) terms are n A.P. whose common difference is 2, and the last (2n+1) terms are in G.P. whose common ratio is 0.5 if the middle terms of the A.P. and LG.P. are equal ,then the middle terms of the sequence is (n .2 n+1)/(2^(2n)-1) b. (n .2 n+1)/(2^n-1) c. n .2^n d. none of these

a,b,c are in G.P. and a+b+c=xb , x can not be (a) 2 (b) -2 (c) 3 (d) 4

If the roots x^5-40 x^4+P x^3+Q x^2+R x+S=0 are n G.P. and the sum of their reciprocals is 10, then |S| is 4 b. 6 c. 8 d. none of these