If the curves `a y+x^2=7 and x^3=y` cut orthogonally at `(1,1)` , then find the value `adot`

If the curves ay + x^(2) = 7 and y = x^(3) cut orthogonally at (1,1) , then the value of a is

If the curve a y+x^2=7 and x^3=y cut orthogonally at (1,\ 1) , then a is equal to (a) 1 (b) -6 (c) 6 (d) 0

If the curves ay+x^2=7 and x^3=y cut orthogonally at (1, 1) then a= (A) 1 (B) -6 (C) 6 (D) 1/6

Show that x^2=y and x^3+6y=7 intersect orthogonally at (1,\ 1)

If curve y = 1 - ax^2 and y = x^2 intersect orthogonally then the value of a is

The curves y =ae^(-x) and y=be^(x) be orthogonal , if

If the curves 2x^(2)+3y^(2)=6 and ax^(2)+4y^(2)=4 intersect orthogonally, then a =

If 4x^(2)+ py^(2) =45 and x^(2)-4y^(2) =5 cut orthogonally, then the value of p is

If 4x^(2)+ py^(2) =45 and x^(2)-4y^(2) =5 cut orthogonally, then the value of p is

If curve x^2=9a(9-y) and x^2=a(y+1) intersect orthogonally then value of 'a' is