How many roots of the equation `3x^(4) + 6x^(3) + x^(2) + 6x + 3 = 0` are real ?

Each of the roots of the equation x^(3) - 6x^(2) + 6x - 5 = 0 are increased by k so that the new transformed equation does not contain x^(2) term. Then k =

Find the roots of the equation 3x^2+6x+3=0

Find how many roots of the equations x^4+2x^2-8x+3=0.

Find how many roots of the equations x^4+2x^2-8x+3=0.

For k gt 0 if k sqrt(-1) is a root of the equation x^4 + 6x^3 - 16x^2 + 24 x- 80 =0 then k^2 =

the roots of the equation x^4 -6x^3 + 18x^2- 30 x +25 =0 are of the form a +- i b and b +- ia then (a ,b)=

Using differentiation method check how many roots of the equation x^3-x^2+x-2=0 are real?

If alpha, beta, gamma are the roots of the equation x^(4)+Ax^(3)+Bx^(2)+Cx+D=0 such that alpha beta= gamma delta=k and A,B,C,D are the roots of x^(4)-2x^(3)+4x^(2)+6x-21=0 such that A+B=0 The value of C/A is

If alpha, beta, gamma are the roots of the equation x^(4)+Ax^(3)+Bx^(2)+Cx+D=0 such that alpha beta= gamma delta=k and A,B,C,D are the roots of x^(4)-2x^(3)+4x^(2)+6x-21=0 such that A+B=0 The correct statement is

Solve the equation x^4 -6x^3 +18x^2 - 30 x+ 25 =0 given that 2+i is a root