Find the equation of tangent to the curve `y=sin^(-1)(2x)/(1+x^2)a tx=sqrt(3)`

Find the equation of the tangent to the curve y=x-sinxcosx at x=pi/2

The equation of the tangent to the curve y = e^(2x) at (0,1) is

Find the equation of the normal to the curve y=(1+y)^y+sin^(-1)(sin^2x)a tx=0.

Find the equation of the normal to the curve y=(1+x)^y+sin^(-1)(sin^2x) at x=0.

Find the equation of the normal to the curve y=(1+x)^y+sin^(-1)(sin^2x) at x=0.

Find the equation of tangent of the curve 6y=9-3x^(2) at point (1,1).

Find the equation of tangent to the curve given by x=2 sin^(3)t ,y=2 cos^(3)t at a point where t=(pi)/(2) ?

Find the equation of the tangent to the curve y=(x-7)/((x-2)(x-3) at the point where it cuts the x-axis.

if |f(x_1)-f(x_2)|<=(x_1-x_2)^2 Find the equation of tangent to the curve y= f(x) at the point (1, 2).

Find the equation of the tangent to the curve (x^2)/(a^2)+(y^2)/(b^2)=1 at (x_1,\ y_1) on it.