Find the equation of the normal to the curve `y=(1+x)^y+sin^(-1)(sin^2x) at `x=0.`

Find the equation of the normal to the curve y=(1+y)^y+sin^(-1)(sin^2x)a tx=0.

The equation of the normal to the curve y = sin x at (0,0) is

Find the equation of the normal to the curve x^2/a^2-y^2/b^2=1 at (x_0,y_0)

Find the equation of tangent and normal to the curve 2y=3-x^(2) at (1, 1).

Find the equation of tangent to the curve y=sin^(-1)(2x)/(1+x^2)a tx=sqrt(3)

The slope of the normal to the curve y=2x^(2)+3 sin x at x = 0 is

Find the equations of the tangent and the normal to the curve y=x^2+4x+1 at x=3 at the indicated points

Equation of the normal to the curve y=-sqrt(x)+2 at the point (1,1)

Find the equation of normal to the curve x = a cos^(3)theta, y=b sin^(3) theta" at point "'theta'.

Find the equations of the tangent and the normal to the curve y=2x^2-3x-1 at (1,\ -2) at the indicated points