Let `f(x)`=`{-x^2`,for `x<0x^2+8`,for `xgeq0` Find x intercept of tangent to f(x) at x =0 .

Let f(x)=min{x,x^2} , for every x in R . Then

Let f(x)={(x^2,x notin Z),((k(x^2-4))/(2-x),x notinZ):} Then, lim_(xto2) f(x)

Let f(x)={{:(-|x-2|, ,x le 3 ),(x^(2)-2x-4,, x gt 3 ):} Then the number of critical points on the graph of the function is

Let f(x)={x^2-4x+3, ,x<3; x-4,xgeq3 a n d g(x)={x-3,x<4; x^2+2x+2,xgeq4 Describe the function f/g and find its domain.

Let f(x)=x^(2)-x+1, AA x ge (1)/(2) , then the solution of the equation f(x)=f^(-1)(x) is

Let f(x) = x^2, g(x) = sin x, h(x) =sqrtx, then verify that [fo(goh)] (x) and [(fog)oh] (x) are equal.

Let f(x)={(1+|x-2|, ,x!=2), (2, , x=2):} then at x=2, f(x) has

let f(x) = {:{( x^(2) , x le 0) , ( ax , x gt 0):} then f (x) is derivable at x = 0 if

Let f(x)={x^2|(cos)pi/x|, x!=0 and 0,x=0,x in RR, then f is

Let f(x) =x^(2) , x in (-1,2) Then show that f(x) has exactly one point of local minima but global maximum Is not defined.