In the expansion of `(3^(-x//4)+3^(5x//4))^(n)` the sum of binomial coefficient is 64 and term with the greatest binomial coefficient exceeds the third by `(n-1)` , the value of `x` must be `0` b. `1` c. `2` d. `3`

Explanation

To solve the problem, we will follow these steps:

### Step 1: Understanding the Binomial Expansion
The expression given is \((3^{-\frac{x}{4}} + 3^{\frac{5x}{4}})^n\). The sum of the binomial coefficients in the expansion is given to be 64.

### Step 2: Finding the Value of \(n\)
The sum of the binomial coefficients in the expansion of \((a + b)^n\) is given by \(2^n\). Therefore, we can set up the equation:
\[
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