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If (1+x^(2))^(n) = underset(r=0)overset(...

If `(1+x^(2))^(n) = underset(r=0)overset(n)suma_(r)x^(r )= (1+x+x^(2)+x^(3))^(100)`. If `a = underset(r=0)overset(300)suma_(r)`, then `underset(r=0)overset(300)sumra_(r)` is

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let underset(r=0)overset(2010)(sum)a_(r)x^(r)=(1+x+x^(2)+x^(3)+x^(4)+x^(5))^(402) and underset(r=0)overset(2010)(sum)a_(r)=a, then the value of ((underset(r=0)overset(2010)(sum)r.a_(r))/(underset(r=0)overset(2010)(sum)a_(r))) is equal to____.

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CENGAGE ENGLISH-BINOMIAL THEOREM-All Questions
  1. If sum(r=0)^(n)((r+2)/(r+1)).^n Cr=(2^8-1)/6 , then n is (A) 8 (B...

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  2. Let f(x)=a0+a1x+a2x^2+...+an x^n and (f(x))/(1-x)=b0+b1x+b2x^2+...+bn ...

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  3. If (1+x^(2))^(n) = underset(r=0)overset(n)suma(r)x^(r )= (1+x+x^(2)+x^...

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  4. The value of sum(r=1)^(n+1)(sum(k=1)^n "^k C(r-1))( where r ,k ,n in ...

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  5. If (x^2+x+1)/(1-x)=a0+a1x+a2x^2+ ,t h e nsum(r=1)^(50)ar is equal to 1...

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  6. Find dy/dt , if y = (1 - cost)/(1 + cost) is

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  7. The coefficient of x^9 in the expansion of (1+x)(1+ x^2)(1+x^3)....(1...

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  8. The coefficients of three consecutive terms of (1+x)^(n+5) are in the ...

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  9. If (1-x)^(-n)=a0+a1x+a2x^2+...+ar x^r+ ,t h e na0+a1+a2+...+ar is equa...

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  10. The value of sum(r=0)^(20)r(20-r)(.^(20) Cr)^2 is equal to a. 400^(...

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  11. The coefficient of x^(10) in the expansion of (1+x^2-x^3)^8 is 476 b. ...

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  12. If the term independent of x in the (sqrt(x)-k/(x^2))^(10) is 405, the...

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  13. The coefficient of x^2y^3 in the expansion of (1-x+y)^(20) is (20 !)/(...

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  14. The coefficient of x^5 in the expansion of (x^2-x-2)^5 is -83 b. -82 c...

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  15. The coefficient of a^8b^4c^9d^9 in (a b c+a b d+a c d+b c d)^(10) is...

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  16. If the coefficient of x^7in[a x^2-(1/(b x^2))]^(11) equal the coeffici...

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  17. If (1+x)^5=a0+a1x+a2x^2+a3x^3+a4x^4+a5x^5, then the value of (a0-a2+a4...

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  18. The coefficient of x^n in the expansion of (1+x)(1-x)^n is

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  19. The coefficient of x^(28) in the expansion of (1+x^3-x^6)^(30) is a...

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  20. The coefficient of x^n in (1+x)^(101)(1-x+x^2)^(100) is non zero, then...

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