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If (4+sqrt(15))^n=I+f,where n is an odd ...

If `(4+sqrt(15))^n=I+f,`where `n` is an odd natural number, `I` is an integer and ,then a.`I`is an odd integer b. `I`is an even integer c. `(I+f)(1-f)=1` d. `1-f=(4-sqrt(15))^n`

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