For the function f(x)=x^4(12(log)e x-7),...

For the function `f(x)=x^4(12(log)_e x-7),` the point (1,7) is the point of inflection. `x=e^(1/3)` is the point of minima the graph is concave downwards in (0,1) the graph is concave upwards in `(1,oo)`

AI Generated Solution

Similar Questions

Explore conceptually related problems

Prove that the function f(x)=(log)_e x is increasing on (0,\ oo) .

Draw the graph of y=sin^(-1)("log"_(e)x) . Also find the point of inflection.

Draw the graph of f(X)=log_(e)(1-log_(e)x) . Find the point of inflection

Draw the graph of f(x) = e^(x)/(1+e^(x)) . Also find the point of inflection.

Draw the graph of f(x)="ln" (1-"ln "x) . Find the point of inflection.

Draw the graph of f(x)=e^(-x^(2)) . Discuss the concavity of the graph.

Find the coordinates of the point of inflection of the curve f(x) =e^(-x^(2))

Find the points of maxima minima of f(x) =x^(3) -12 x. Also draw the graph of this functions.

The point (2, -1) on the graph y=f(x) is shifted to which point on the graph of y=f(x+2)?

Prove that the function f(x)=(log)_e(x^2+1)-e^(-x)+1 is strictly increasing AAx in Rdot