Tangents are drawn to `x^2+y^2=16` from the point `P(0, h)dot` These tangents meet the `x-a xi s` at `Aa n dB` . If the area of triangle `P A B` is minimum, then `h=12sqrt(2)` (b) `h=6sqrt(2)` `h=8sqrt(2)` (d) `h=4sqrt(2)`

Tangents P Aa n dP B are drawn to x^2+y^2=a^2 from the point P(x_1, y_1)dot Then find the equation of the circumcircle of triangle P A Bdot

Tangents are drawn to the circle x^2 + y^2 = 32 from a point A lying on the x-axis. The tangents cut the y-axis at points B and C , then the coordinate(s) of A such that the area of the triangle ABC is minimum may be: (A) (4sqrt(2), 0) (B) (4, 0) (C) (-4, 0) (D) (-4sqrt(2), 0)

Tangents are drawn to the circle x^2+y^2=50 from a point "P lying on the x-axis. These tangents meet the y-axis at points 'P_1,' and 'P_2 . Possible co-ordinates of 'P' so that area of triangle PP_1P_2 is minimum is/are -

If A is the area an equilateral triangle of height h , then (a) A=sqrt(3)\ h^2 (b) sqrt(3)A=h (c) sqrt(3)A=h^2 (d) 3A=h^2

A circle passes through the points A(1,0) and B(5,0), and touches the y-axis at C(0,h)dot . If /_A C B is maximum, then (a) h=3sqrt(5) (b) h=2sqrt(5) (c) h=sqrt(5) (d) h=2sqrt(10)

From point P(4,0) tangents PA and PB are drawn to the circle S: x^2+y^2=4 . If point Q lies on the circle, then maximum area of triangleQAB is- (1) 2sqrt3 (2) 3sqrt3 (3) 4sqrt3 A) 9

Consider the parabola whose focus is at (0,0) and tangent at vertex is x-y+1=0 The length of latus rectum is (a) 4sqrt(2) (b) 2sqrt(2) (c) 8sqrt(2) (d) 3sqrt(2)

If the equation of base of an equilateral triangle is 2x-y=1 and the vertex is (-1,2), then the length of the sides of the triangle is sqrt((20)/3) (b) 2/(sqrt(15)) sqrt(8/(15)) (d) sqrt((15)/2)

The distance between the directrices of the hyperbola x=8s e ctheta,\ y=8\ t a ntheta, a. 8sqrt(2) b. 16sqrt(2) c. 4sqrt(2) d. 6sqrt(2)

The abscissa of the point on the curve sqrt(x y)=a+x the tangent at which cuts off equal intercepts from the coordinate axes is -a/(sqrt(2)) (b) a//sqrt(2) (c) -asqrt(2) (d) asqrt(2)