Using the relation `2(1−cosx)`<`x^2` ,`x=0` or prove that `sin(tanx)≥x,∀ϵ[0,π/4]`

The number of solutions of the equation (secx)/(1-cosx)=1/(1-cosx) in [0,\ 2pi] is equal to 3 (b) 2 (c) 1 (d) 0

Solutions of the equations (2cosx-1)(3cosx+4)=0 is [0,2pi] is:

Integrate the functions (1-cosx)/(1+cosx)

Integrate the functions (cosx)/(1+cosx)

Using constraint method find the relation between accelerations of 1 and 2 .

Using constraint method find the relation between of a_(1) and a_ (2) .

Using contraint equation. Find the relation between a_(1) and a_(2).

Find the solution of cosx = 1/2 .

If x_(1),x_(2),...,x_(n) are real numbers, then the largest value of the expression sinx_(1)cosx_(2)+sinx_(2)cosx_(3)+...+sinx_(n)cosx_(1), is

solve equation 2 tan^(-1)(cosx)=tan^(-1)(2cosecx)