`f(x)=4tanx-tan^2x+tan^3x ,x!=npi+pi/2,` (a)is monotonically increasing (b)is monotonically decreasing (c)has a point of maxima (d)has a point of minima

f(x) = 4 tan x-tan^(2)x+tan^(3)x,xnenpi+(pi)/(2)

F(x) = 4 tan x-tan^(2)x+tan^(3)x,xnenpi+(pi)/(2)

the function (|x-1|)/x^2 is monotonically decreasing at the point

In the interval (1,\ 2) , function f(x)=2|x-1|+3|x-2| is (a) monotonically increasing (b) monotonically decreasing (c) not monotonic (d) constant

Let f(x) =x - tan^(-1)x. Prove that f(x) is monotonically increasing for x in R

Let f(x)=|x^2-3x-4|,-1lt=xlt=4 Then f(x) is monotonically increasing in [-1,3/2] f(x) monotonically decreasing in (3/2,4) the maximum value of f(x)i s(25)/4 the minimum value of f(x) is 0

Let f(x) = tan^-1 (g(x)) , where g (x) is monotonically increasing for 0 < x < pi/2.

If f(x)=k x^3-9x^2+9x+3 monotonically increasing in R , then

If g(x) is monotonically increasing and f(x) is monotonically decreasing for x in R and if (gof) (x) is defined for x in R , then prove that (gof)(x) will be monotonically decreasing function. Hence prove that (gof) (x +1)leq (gof) (x-1).

If g(x) is monotonically increasing and f(x) is monotonically decreasing for x R and if (gof) (x) is defined for x e R, then prove that (gof)(x) will be monotonically decreasing function. Hence prove that (gof) (x +1)leq (gof) (x-1).