Consider the system of the equation `k x+y+z=1,x+k y+z=k ,a n dx+y+k z=k^2dot` Statement 1: System equations has infinite solutions when `k=1.` Statement 2: If the determinant `|1 1 1k k1k^2 1k|=0,` t hen `k=-1.`

Consider the system of equations x-2y+3z=1;-x+y-2z=; x-3y+4z=1. Statement 1: The system of equations has no solution for k!=3. Statement2: The determinant |1 3-1-1-2k1 4 1|!=0,\ for\ k!=3. Statement 1 is True: Statement 2 is True; Statement 2 is a correct explanation for statement 1 Statement 1 is true, Statement 2 is true;2 Statement 2 not a correct explanation for statement 1. Statement 1 is true, statement 2 is false Statement 1 is false, statement 2 is true

Consider the system of equations x-2y+3z=-1 -x+y-2z=k x-3y+4z=1 Statement -1 The system of equation has no solutions for k ne 3 . statement -2 The determinant |{:(1,3,-1),(-1,-2,k),(1,4,1):}| ne0, "for"" " kne3.

A solution set of the equations x+2y+z=1 , x+3y+4z=k , x+5y+10z=k^(2) is

For what value of 'K', the system of equations kx+y+z=1, x+ky+z=k" and "x+y+kz=K^(2) has no solution ?

The system of simulataneous equations kx + 2y -z = 1 (k -1) y -2z = 2 (k +2) z = 3 have a unique solution if k equals

If the system of equations 3x+y=1,\ \ (2k-1)x+(k-1)y=2k+1 is inconsistent, then k=

Let the following system of equations {:(kx+y+z=1),(x+ky+z=k),(x+y+kz=k^2):} has no solution . Find |k|.

For what value of k does the system of linear equations 2x+3y=7 and (k-1)x + (k+2)y =3k have an infinite number of solutions

The system of equations {:(kx+(k+1)y+(k-1)z=0),((k+1)x+ky+(k+2)z=0),((k-1)x + (k+2)y+kz=0):} has a nontrivial solution for :

The number of values of k for which the system of the equations (k+1)x+8y=4k and k x+(k+3)y=3k-1 has infinitely many solutions is 0 b. 1 c. 2 d. infinite