The function `y=(2x-1)/(x-2),(x!=2)` (a)is its own inverse (b)decrease at all values of `x` in the domain (c)has a graph entirely above the `x-` axis (d)is unbounded.

Graph function. y=|x+2|+x

The function y=(a x+b)/((x-1)(x-4)) has turning point at P(2,1)dot Then find the value of a\ a n d\ bdot

For which values of x , the function f(x)=x/(x^2+1) is increasing and for which values of x , it is decreasing.

Discuss the function y=x+In(x^(2)-1) and plot its graph.

For which values of x , the function f(x)=x/(x^2+1) is increasing and for which value of x , it is decreasing.

Statement 1: For all a ,b in R , the function f(x)=3x^4-4x^3+6x^2+a x+b has exactly one extremum. Statement 2: If a cubic function is monotonic, then its graph cuts the x-axis only one.

Find the values ' a ' for which the function f(x)=(a+2)x^3-3a x^2+9a x-1 decreases for all real values of x .

If the function f(x)=(x^2)/2+lnx+a x is always monotonically increasing in its domain then the least value of a is 2 (b) -2 (c) -1 (d) 1

If the function f(x)=(x^2)/2+lnx+a x is always monotonically increasing in its domain then the least value of a is 2 (b) -2 (c) -1 (d) 1

The graph of the function y=16x^(2)+8(a+2)x-3a-2 is strictly above the x - axis, then number of integral velues of 'a' is