Solve `[xsin^2(y/x)-y]dx+x dy=0; y=pi/4` when `x=1.`

The differential equations , find the particular solution satisfying the given condition: [xsin^2(y/x)-y]dx+x dy=0; y=pi/4 when x = 1

Solve the differential equation : (xsin^2(y/x)-y)dx+xdy=0 given y=pi/4 when x=1.

Solve the following initial value problem: {xsin^2(y/x)-y}dx+x dy=0,\ y(1)=pi/4

Solve x^2((dy)/(dx))+y=1

Solve x^2((dy)/(dx))+y=1

Solve: x(dy)/(dx)-y=x+1

Solve: x(dy/dx)^2+(y-x)dy/dx-y=0

Solve: x^2dy-y^2dx+xy^2(x-y)dy=0

Solve xsin(y/x)dy=(ysin(y/x)-x)dx .

Solve x(y^2-1)dx - y(x^2-1)dy =0