Home
Class 12
MATHS
Find the equation of a curve passing thr...

Find the equation of a curve passing through `(0,1)` and having gradient `(-(y+y^3))/(1+x+x y^2)` at `(x , y)`.

Text Solution

AI Generated Solution

Promotional Banner

Similar Questions

Explore conceptually related problems

The equation of a curve passing through (2,7/2) and having gradient 1-1/(x^2) at (x , y) is

Find the equation of a curve passing through (1,1) and whose slope of tangent at a point (x, y) is -(x)/(y) .

Find the equation of the curve which passes through the point (3,-4) and has the slope (2y)/x at any point (x , y) on it.

Find the equation of the curve which passes through (1,0) and the slope of whose tangent at (x,y) is (x^2+y^2)/(2xy)

Find the equation of a curve, passes through (-2,3) at which the slope of tangent at any point (x,y) is (2x)/(y^(2)) .

The equation of the curve passing through the point (1,pi/4) and having a slope of tangent at any point (x,y) as y/x - cos^2(y/x) is

The equation of the curve passing through the point (1,pi/4) and having a slope of tangent at any point (x,y) as y/x - cos^2(y/x) is

The equation of the curve passing through the point (1,1) and satisfying the differential equation (dy)/(dx) = (x+2y-3)/(y-2x+1) is

The equation of the curve passing through origin, whose slope at any point is (x(1+y))/(1+x^2) , is (A) (1+y)^2-x^2=1 (B) x^2+(y+1)^2=1 (C) (x+y)y=1-x^2 (D) x=ye^((1+y))

Find the equation of the circle passing through (1,2) and which is concentric with the circle x^2+y^2+11x-5y+3=0.