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Draw a rough sketch of the curve y=(x-1)...

Draw a rough sketch of the curve y=`(x-1)^2(x-2)(x-3)^3`

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Draw the rough sketch of the curve y=(x-1)^(2)(x-2)(x-3)^(3) .

Draw the rough sketch of the curve y=(x-1)^(2)(x-3)^(3) .

Draw a rough sketch of the curve y=(x^2+3x+2)/(x^2-3x+2) and find the area of the bounded region between the curve and the x-axis.

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Draw a rough sketch of the curves y = (x-1)^2 and y = |x-1| . Hence, find the area of the region bounded by these curves.

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CENGAGE ENGLISH-APPLICATION OF INTEGRALS-All Questions
  1. Find the area bounded by x=2y-y^2 and the y-a x i s.

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  2. Find the area bounded by y=sin^(-1)x ,y=cos^(-1)x ,and the X-axis.

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  3. Draw a rough sketch of the curve y=(x-1)^2(x-2)(x-3)^3

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  4. Find the area bounded by (a) y = (log)e|x|a n dy=0 (b) y=|(log)e|x|...

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  5. Sketch the curves and identity the region bounded by x=1/2,x=2,y=lnx ,...

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  6. Sketch the region bounded by the curves y=x^(2) and y=(2)/(1+x^(2)). F...

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  7. Find the area of the region bounded by the curve C : y=tan x ,tangent ...

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  8. Compute the area of the region bounded by the curves y=e x(log)e xa n ...

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  9. A O B is the positive quadrant of the ellipse (x^2)/(a^2)+(y^2)/(b^2)=...

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  10. Find the area bounded by the curves y=sin x and y=cos x between two co...

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  11. In what ratio does the x-axis divide the area of the region bounded by...

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  12. Consider a square with vertices at (1,1)(-1,1)(-1,-1)and(1,-1). Let S ...

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  13. Find the area bounded by y=x^3-x and y=x^2+xdot

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  14. Find the area, lying above the x=axis and included between the circle ...

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  15. Consider the region formed by the lines x=0,y=0,x=2,y=2. If the area e...

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  16. Find the area bounded by the curve y=(x-1)(x-2)(x-3) lying between the...

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  17. Find the area bounded by the parabola y=x^2+1 and the straight line x+...

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  18. Find the area of the closed figure bounded by the curves y=sqrt(x),y=s...

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  19. Find the area of the smaller part of the circle x^2+y^2=a^2 cut off...

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  20. The area enclosed by the curve c : y=xsqrt(9-x^2) (xgeq0) and the x-ax...

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