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If `fa n dg` are continuous function on `[0,a]` satisfying `f(x)=f(a-x)a n dg(x)+g(a-x)=2,` then show that `int_0^af(x)g(x)dx=int_0^af(x)dxdot`

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If fa n dg are continuous function on [0,a] satisfying f(x)=f(a-x)a n dg(x)(a-x)=2, then show that int_0^af(x)g(x)dx=int_0^af(x)dxdot

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